Question

Two cars simultaneously left Points A and B and headed towards each other, and met after 3 hours and 15 minutes. The distance between points A and B is 364 miles. What is the speeds of the cars, if one of the cars travels 12 mph faster than the other?

Answer 1

50 mph, 62 mph

Explanation:

Their total speed is found from ...

speed = distance/time

speed = (364 mi)/(3.25 h) = 112 mi/h

If s is the speed of the slower car, then ...

s + (s+12) = 112 . . . . . their total speed is 112 mph

2s = 100 . . . . . . . . . . simplify, subtract 12

s = 50 . . . . . . . the speed of the slower car

s+12 = 62 . . . . the speed of the faster car

Answer 2

Speed of one car=50 mph

Speed of another car=50+12=62 mph

Explanation:

Speed of one car= x mile/hr

Speed of another car=(x+12) miles/hr

Time=3 hours 15 minutes=
`3+(15)/(60)=(13)/(4) hr`

Because 1 hr=60 minutes

Distance between point A and B=364 miles

Distance =
`speed* time`

According to question

`(13)/(4)x+(13)/(4)(x+12)=364`

`(13x)/(4)+(13x)/(4)+39=364`

`(26x)/(4)=364-39=325`

`(13x)/(2)=325`

`x=(325* 2)/(13)=50`

Speed of one car=50 mph

Speed of another car=50+12=62 mph