Question

A football is kicked from ground level with an initial velocity of 22.2 m/s at angle of 31.0° above the horizontal. How long, in seconds, is the football in the air before it hits the ground?

Answer 1

t = 1.66 seconds

Step-by-step explanation:

Initial velocity of the football, u = 22.2 m/s

Angle above the horizontal,
`\theta=31^(\circ)`

Let
`v_y` is the vertical component of the velocity,

`u_y=u\ sin\theta`

`u_y=22.2\ sin(31)=11.43\ m/s`

Let t is the time for which the football in the air before it hits the ground. It can be calculated as :

`v=u_y-gt`

v = 0

`u_y=gt`

`t=(u_y)/(g)`

`t=(11.43)/(9.8)`

t = 1.66 seconds

Hence, this is the required solution.