Question

Compute the energy and momentum of a single photon of visible light for wavelengths of 4000 A, 6000 A, and 8000 A, where 1 10-10 meter. Repeat for an infrared photon of 1,000,000 A and an ultra- violet photon of 500 A. Comment on the results.

Answer 1

Step-by-step explanation:

To calculate the energy we will use the Planck equation and to calculate the moment we will use the Brolle equation

E = h f

P = h / λ

With the constant that is worth 6.63 10-34 J s

Wavelengths are λ= 4000 A = 4000 10-10 = 4 10-7 m

The speed of light is the product of the frequency by the wavelength of the radiation

c = λ f

f = c / λ

f = 3 10⁸/4 10⁻⁷

f = 7.5 10¹⁴ Hz

E = 6.63 10⁻³⁴ /7.5 10¹⁴

E = 49.7 10⁻⁴⁸ J

P = 6.63 10⁻³⁴ / 4 10⁻⁷

P = 1.66 10⁻²⁷

λ = 6000 A = 6 10⁻⁷ m

f = 3 108/5 10-7 = 5 10¹⁴ Hz

E = 6.63 10⁻³⁴ / 5 10¹⁴ = 1.3 10⁻⁴⁸ Hz

P = 6.63 10⁻³⁴ / 6 10⁻⁷ = 1.1 10⁻²⁷

λ = 8000 a = 8 10⁻⁷

f = 3 10⁸/8 10⁻⁷ = 3.75 10¹⁴ Hz

E = 6.63 10⁻³⁴ / 3.75 10¹⁴ = 1.77 10⁻⁴⁸ Hz

P = 6.63 10⁻³⁴ / 8 10⁻⁷ = 8.2 10⁻²⁷

λ = 1000000 = 1 10⁻⁴ m

f = 3 10⁸/1 10⁻⁴ = 3 10¹² Hz

E = 6.63 10⁻³⁴ / 3 10¹² = 2.21 10⁻⁴⁶ Hz

P = 6.63 10⁻³⁴ / 8 10⁻⁷ = 8.2 10⁻²⁷

λ = 500 A = 5 10⁻⁸ m

f = 3 10⁸/5 10⁻⁸ = 6 10¹⁵ Hz

E = 6.63 10⁻³⁴ / 5 10¹⁵ = 1.33 10⁻⁴⁹ Hz

P = 6.63 10⁻³⁴ / 5 10⁻⁸ = 1.33 10⁻²⁶ Kg m / s²

We see that the energy of the ultraviolet photon is much greater (two orders of magnitude) than that of the infrared photon