Question

A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient. If 2 unit doses are used, how many mg of active ingredient are used?

Answer 1

Answer: 0.42 mg

Explanation:

Given : A 3mL unit dose of levalbuterol HCl contains 0.63mg of active ingredient.

Then , the amount of active ingredient in 1 ml dose of levalbuterol HCl =
`(0.63)/(3)`

`=(63)/(300)=(21)/(100)=0.21\ mg`

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl will be :-

`2*0.21=0.42\ mg`

Hence, the amount of active ingredient in 2 ml dose of levalbuterol HCl =0.42 mg