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2 votes
One cubic meter of an ideal gas at 600 K and 1000 KPa expand to five times its initial volume as follows:

(a) By a mechanically reversible, isothermal process [T 2 = 600K; P 2 = 200kPa; W= -1609 kJ]


(b) By a mechanically reversible, adiabatic process [T 2 =208.96K; P 2 = 67.65 kPa; W= -994.4 kJ] For each case calculate the final temperature, pressure and the work done by the gas. C p =21 Jmol- 1K-1.

1 Answer

1 vote

Answer:

lol just grabbing your points

Step-by-step explanation:lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

lol just grabbing your points

answered
User Litehouse
by
8.1k points
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