What is the equation of the line that is perpendicular to the given line and has an x-intercept of 6? y = –Three-fourthsx + 8 y = –Three-fourthsx + 6 y = Four-thirdsx – 8 y = Fo…

Question

asked Aug 27, 2020 185k views

2 Answers

Michael Erickson · Answer 1 · 2020-08-31T08:37:52+0000

Answer:

y=(4)/(3)x-8

Option 3 is correct

Explanation:

To find: The equation of perpendicular to given line and has x-intercept 6

x-intercept is on x-axis where y value is 0.

Therefore, x-intercept: (6,0)

Now we will check each point for each option.

Option 1:
y=-(3)/(4)x+8

Put x=6, y=0

$0=-(3)/(4)\cdot 6+8$

$0\\eq(7)/(2)$

False

Option 2:
y=-(3)/(4)x+6

Put x=6, y=0

$0=-(3)/(4)\cdot 6+6$

$0\\eq(3)/(2)$

False

Option 3:
y=(4)/(3)x-8

Put x=6, y=0

$0=(4)/(3)\cdot 6-8$

0=0

True

Option 1:
y=(4)/(3)x-6

Put x=6, y=0

$0=(4)/(3)\cdot 6-6$

$0\\eq2$

False

Hence, The perpendicular equation is
y=(4)/(3)x-8