Question

On a distant planet, golf is just as popular as it is on earth. A golfer tees off and drives the ball 3.70 times as far as he would have on earth, given the same initial velocities on both planets. The ball is launched at a speed of 41.2 m/s at an angle of 31 ° above the horizontal. When the ball lands, it is at the same level as the tee. On the distant planet, what are (a) the maximum height and (b) the range of the ball?

Answer 1

a)H=84.87 m

b)R=565.27 m

Step-by-step explanation:

Given that

Speed of ball on earth

U=41.2 m/s

θ=31°

We know that

Maximum height in projectile motion given as

`h=(U^2sin^2\theta )/(2g)`

`h=(41.2^2sin^231)/(2* 9.81)`

h=22.94 m

Range in projectile motion given as

`r=(U^2sin2\theta )/(g)`

`r=(41.2^2sin62 )/(g)`

r=152.77 m

Given that on distance planet ball moves 3.7 times far more as on earth.

So on the distance planet

The maximum height ,H=3.7 h

H= 3.7 x 22.94

H=84.87 m

The range on distance planet

R=3.7 r

R=3.7 x 152.77 m

R=565.27 m