Question

Suppose the equation for line A is given by 12x=9y+27. If line A and B are perpendicular and the point (16,-12) lies on line B, then write the equation for line B

Answer 1

The answer is -3/4x

Explanation:

I just did it and I got it right .

Answer 2

`y=-(3)/(4) x-8`

Explanation:

he equation for line A is given by 12x=9y+27

Equation of line is y=mx+b where m is the slope

`12x=9y+27`

Subtract 27 on both sides

`12x-27=9y`

Divide both sides by 9

`y=(4)/(3) x-3`

Slope of the given line is 4/3

Slope of perpendicular lines are negative reciprocal of one another

slope of perpendicular line is -3/4

`m=-3/4, (16,-12)`

`y-y1=m(x-x1)`

`y+12=(-3)/(4)(x-16)`

Multiply fraction inside the parenthesis

`y+12=-(3)/(4) x+4`

Now subtract 12 from both sides

`y=-(3)/(4) x-8`