Question

The roof of the Terminal Tower is 709 feet above ground. A window washer dropped a bucket from the edge of the roof. How many seconds did it take for the bucket to hit the ground? Round to the nearest second

Answer 1

6.64 seconds

Explanation:

Given that:

Distance between roof of the terminal and ground = 709 feet

A bucket was dropped from the roof.

To find:

The time taken by the bucket to hit the ground?

Solution:

Distance traveled,
`s` = 709 feet

Initial velocity of the bucket,
`u` = 0 feet/sec (because initially it was at rest)

Acceleration of the bucket will be equal to acceleration due to gravity i.e.

`g` or 32.1741
`ft/sec^(2)`

Let the time taken is
`t` seconds.

Formula for distance is given as:

`s = ut+(1)/(2)at^2`

Putting all the values:

`709 = 0 (t) + (1)/(2)(32.1741) t^2\\\Rightarrow 1418 = 32.1741 t^2\\\Rightarrow t^2 = 44.07\\\Rightarrow t \approx \bold{6.64\ sec}`