Question

The metal rhodium becomes superconducting at temperature below 0.0003k . Calculate the temperature at which rhodium becomes superconducting in degrees censius . Round your answer to 4 decimal places

Answer 1

Rhodium becomes superconducting at a temperature of -273.1497°C when rounded to four decimal places.

Step-by-step explanation:

The temperature at which rhodium becomes superconducting is below 0.0003 Kelvin (K). To convert this temperature to degrees Celsius (°C), we use the formula °C = K - 273.15. Substituting 0.0003 K into the formula, we get:

°C = 0.0003 K - 273.15 = -273.1497°C

Therefore, rhodium becomes superconducting at a temperature of -273.1497°C, rounded to four decimal places.

Answer 2

`\large \boxed{\text{-273.1497 $^(\circ)$\text{C}}}`

Step-by-step explanation:

`\begin{array}{rcl}C & = & K - 273.15\\& = & 0.0003 - 273.15\\& = & \mathbf{-273.1497}\\\end{array}\\\text{Rhodium becomes superconducting at $\large \boxed{\textbf{-273.1497 $^(\circ)$\text{C}}}$}`