Approximate the field by treating the disk as a +6.7 μ C point charge at a distance of 48 cm.

Question

asked Apr 10, 2020 130k views

1 Answer

Alan Feekery · Answer 1 · 2020-04-16T23:26:14+0000

Answer:

E = 2.62 * 10^5 N/C

Step-by-step explanation:

Electric field due to a point charge is given as

E = (kq)/(r^2)

here we know that

$q = 6.7 \mu C$

r = 48 cm

now plug in all values in it

$E = ((9* 10^9)(6.7\mu C))/(0.48^2)$

E = 2.62 * 10^5 N/C

so here electric field is given due to point charge as above