Question

What is the density, in Mg/m3, of a substance with a density of 0.14 lb/in3? (3 pts) What is the velocity, in m/sec, of a vehicle traveling 70 mi/hr?

Answer 1

`276.74* 10^8Mg/m^3`

31.29 m/sec

Step-by-step explanation:

We have given density of substance
`0.14lb/in^3`

We have convert this into
`Mg/m^3`

We know that 1 lb = 0.4535 kg. so 0.14 lb = 0.14×0.4535 = 0.06349 kg

We know that 1 kg = 1000 g ( 1000 gram )

So 0.06349 kg = 63.49 gram

And we know that 1 gram = 1000 milligram

So 63.49 gram
`=63.49* 10^3\ Mg`

We know that
`1 in^3=1.6387* 10^(-5)m^3`

So
`0.14in^3=0.14* 1.6387* 10^(-5)=0.2294* 10^(-5)m^3`

So
`0.14lb/in^3` =\frac{63.49\times 10^3}{0.2249\times 10^{-5}}=276.74\times 10^8lb/m^3[/tex]

In second part we have to convert 70 mi/hr to m/sec

We know that 1 mi = 1609.34 meter

So 70 mi = 70×1609.34 = 112653.8 meter

1 hour = 3600 sec

So 70 mi/hr
`=(70* 1609.34meter)/(3600sec)=31.29m/sec`