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Ii) (1 + x) y dx + ( 1 +y ) x dy = 0.​

Ii) (1 + x) y dx + ( 1 +y ) x dy = 0.​
asked 224k views
2 votes
Ii) (1 + x) y dx + ( 1 +y ) x dy = 0.​

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User MSalters
by
8.4k points

1 Answer

3 votes

Answer:

Explanation:


(1 + x)ydx + (1 + y)xdy = 0


(1 + y)xdy = -(1 + x)ydx


dy = (-(1 + x)ydx)/((1 + y)x)


(dy)/(dx) = (-(1 + x)y)/((1 + y)x)

answered
User Azizj
by
8.5k points
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