Question

How many electrons would have to be removed from a coin to leave it with a charge of +1.5 × 10^-5 C?

Answer 1

`9.375* 10^(13)electron` leave out with a charge of
`1.5* 10^(-5)C`

Step-by-step explanation:

We have given total charge
`Q=1.5* 10^(-5)C`

We know that charge on one electron =
`1.6* 10^(-19)C`

We have to find the total number of electron in total charge

So
`q=ne`, here q is total charge, n is number of electron and e is charge on one electron

So
`1.5* 10^(-5)=n* 1.6* 10^(-19)`

`n=0.9375* 10^(14)=9.375* 10^(13)electron`

So
`9.375* 10^(13)electron` leave out with a charge of
`1.5* 10^(-5)C`