Question

Given the function f(x)=x2+2x+1, find:
f( 2a−3/5 )

Answer 1

`f(2a-(3)/(5))=4a^2+(8a)/(5)+(4)/(25)`

Explanation:

we have

`f(x)=x^(2) +2x+1`

Find
`f(2a-(3)/(5))`

That means -----> substitute the value of
`x=(2a-(3)/(5))` in the function and evaluate

`f(2a-(3)/(5))=(2a-(3)/(5))^(2) +2(2a-(3)/(5))+1`

`f(2a-(3)/(5))=(4a^2-(12a)/(5)+(9)/(25))+(4a-(6)/(5))+1`

`f(2a-(3)/(5))=4a^2+(8a)/(5)-(21)/(25)+1`

`f(2a-(3)/(5))=4a^2+(8a)/(5)+(4)/(25)`