Question

-) A sample of oxygen had an initial volume of 25.0L and was at a standard pressure of

30atm, what would the new volume be if the pressure was increased to 55.00 atm?

Answer 1

13.64 L

Step-by-step explanation:

The new volume can be found by using the formula for Boyle's law which is

`P_1V_1 = P_2V_2`

From the question we have

`V_2 = (P_1V_1)/(P_2) \\`

From the question we have

`V_2 = (25 * 30)/(55) = (750)/(55) \\ = 13.636363...`

We have the final answer as

13.64 L

Hope this helps you