Question

Write the equation of the line perpindicular to the graph of 2x-5y=0 that passes through the point (-2,3)

Answer 1

5x-2y=-4

Explanation:

2x-5y=0

eq. of line perpendicular to ax+by=c is bx-ay=d,d is calculated by the given condition.

line perpendicular to 2x-5y=0 is 5x+2y=c

if it passes through (-2,3) ,then

5*-2+2*3=c

c=-10+6=-4

reqd. eq. is 5x+2y=-4