Question

Calculate the density of helium in lbs/yd cubed A balloon with a capacity of 5.00 L holds 0.890 g.​

Answer 1

`\large \boxed{0.300\text{ lb/yd}^(3)}`

Step-by-step explanation:

`\rho = (m)/(V)\\\\m = \text{0.890 g } * \frac{\text{1 lb}}{\text{453.6 g}} = 1.962 * 10^(-3)\text{ lb}\\\\V = \text{5.00 L} * \frac{\text{1 yd}^(3)}{\text{764.6 L}} =6.539 * 10^(-3) \text{ yd}^(3)\\\\\rho = \frac{1.962 * 10^(-3)\text{ lb}}{6.539 * 10^(-3) \text{ yd}^(3)} = \textbf{0.300 lb/yd}^(3)\\\\\text{The density of helium is }\large \boxed{\mathbf{0.300}\textbf{ lb/yd}^{\mathbf{3}}}`