Question

A baseball, hit 7 feet above the ground, leaves the bat at an angle of 75 and its caught by an outfielder 7 feet above the ground and 300 feet from home plate. How high does the ball rise? Round your answer to the nearest integer.

Answer 1

Answer:139 ft/s

Step-by-step explanation:

Given

ball leaves the bat at angle of
`75^(\circ)`

as the height with ball is launched and height of fielder is same so its vertical displacement is zero and ball is considered to complete a projectile motion with range =300 ft

Also range of projectile is given by

`R=(u^2sin2\theta )/(g)`

where u= launch velocity

`300=(u^2sin150)/(32.2)`

`9660=u^2* 0.5`

`u^2=19,320`

`u=√(19320)=138.99\approx 139 ft/s`