Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

Question

asked Mar 7, 2020 104k views

1 Answer

Pallab · Answer 1 · 2020-03-12T22:46:52+0000

Answer:

The solution of
$\bold{(M^(2))/(P^(2))}$ for M = 10, N = -5P and P = -2 is 25

Solution:

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of
(M^(2))/(P^(2)) ,

By substituting the values of M and N, we get

(M^(2))/(P^(2)) = (10^(2))/((-2)^(2))

Expanding
$\bold{10^(2)}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

10^(2) = 10 * 10 = 100

Similarly expanding
$\bold{(-2)^(2)}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

(-2)^(2) = -2 * -2 = 4

So the equation
(M^(2))/(P^(2)) = (10^(2))/((-2)^(2)) becomes,

(M^(2))/(P^(2)) = (100)/(4)

By dividing 100 by 4 , we get the result as 25

Hence the solution of
$\bold{(M^(2))/(P^(2))}$ when M = 10 and P = -2 is 25