Question

How much CO2 is produced from the combustion of a tank of propane C3H8? Assume the tank contains 9kgs of propane and the molecular weight of propane is 44.1 g/mol

2.7kg 9.0 kg 19.8 kg or 26.9 kg

Answer 1

Answer: The mass of carbon dioxide produced is 26.9 kg

Step-by-step explanation:

To calculate the number of moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}` .....(1)

Given mass of propane = 9 kg = 9000 g (Conversion factor: 1 kg = 1000 g)

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

`\text{Moles of propane}=(9000g)/(44.1g/mol)=204.08mol`

The chemical equation for the combustion of propane follows:

`C_3H_8+5O_2\rightarrow 3CO2+4H_2O`

By Stoichiometry of the reaction:

1 mole of propane produces 3 moles of carbon dioxide.

So, 204.08 moles of propane will produce =
`(3)/(1)* 204.08=612.24mol` of carbon dioxide.

Now, calculating the mass of carbon dioxide by using equation 1, we get:

Molar mass of carbon dioxide = 44.01 g/mol

Moles of carbon dioxide = 612.24 moles

Putting values in equation 1, we get:

`612.24mol=\frac{\text{Mass of carbon dioxide}}{44.01g/mol}\\\\\text{Mass of carbon dioxide}=(612.24mol* 44.01g/mol)=26944.7g=26.9kg`

Hence, the mass of carbon dioxide produced is 26.9 kg