Question

Calculate the factorization 16w^2+48w+36=(4w+[1])^2

need an answer, please
I am trying to find what the [1] is or x

Answer 1

[1] = 6

x = -3/2 is the root

Explanation:

A perfect square trinomial is of the form ...

(a + b)² = a² +2ab +b²

You have ...

• a²=16w² ⇒ a = 4w
• b² = 36 ⇒ b = 6
• 2ab = 2(4w)(6) = 48w

Then the factorization is ...

16w² +48w +36 = (4w +6)²

This will be zero when x = -6/4 = -3/2.