Question

The width of a rectangle is five less than three times the length of the worktable. If the perimeter of the rectangle is 70 inches what are the dimensions of the rectangle?

Answer 1

The dimensions of rectangle whose perimeter is 70 inches and width is five less than three times the length of worktable is length = 10 and width = 25

Solution:

Consider ‘P’ as perimeter and ‘L’ as length and ‘W’ as width

P = 70 inches

W = 5 less than thrice of length

Therefore,
`\mathrm{W}=3 L-5 \quad(\text {equation } 1)`

Using perimeter formula for rectangle,

`\begin{array}{l}{P=2(L+W)} \\ {70=2(L+3 L-5)} \\ {70=2(4 L-5)} \\ {70=8 L-10} \\ {8 L=80} \\ {L=10}\end{array}`

Substitute L= 10 in equation 1

`\begin{aligned} W &=3 * 10-5 \\ W &=30-5 \\ W &=25 \end{aligned}`