Question

3.50 g of an unknown base is dissolved in 289 mL of water and has a concentration of 0.219 M. What is the the identification of the unknown base.

Answer 1

The unknown base should be KOH whose molar mass is 56 g per mol (Answer)

Step-by-step explanation:

Molarity = moles /(Volume in liters)

So,

Moles = Molarity
`*` Volume

`\\$=0.219 M * 289 m L$\\\\$=0.219 (m o l)/(L) * 0.289 L$\\\\$=0.063291 \mathrm{mol}$`

Molar mass = mass/moles

`\\\\$=\frac{3.50 \mathrm{g}}{0.063291 \mathrm{mol}}=55.3 \mathrm{g}$ per mole`

The unknown base should be KOH whose molar mass is 56 g per mol (Answer)