Question

|3x-12|≥6

halp (I have a math test tomorrow can anyone tell my how to simplify/distribute this? ​

Answer 1

see explanation

Explanation:

Inequalities of the type | x | ≥ a always have solutions of the form

x ≤ - a OR x ≥ a, thus

3x - 12 ≤ - 6 or 3x - 12 ≥ 6

3x - 12 ≤ - 6 ( add 12 to both sides )

3x ≤ 6 ( divide both sides by 3 )

x ≤ 2

OR

3x - 12 ≥ 6 ( add 12 to both sides )

3x ≥ 18 ( divide both sides by 3 )

x ≥ 6

Solution is x ≤ 2 OR x ≥ 6