Question

I need to solve for z

Answer 1

`C=(5)/(9)(F-32)`

Explanation:

we have

`F=(9)/(5)C+32`

Solve for C

That means ----> isolate the variable C

Subtract 32 both sides

`F-32=(9)/(5)C+32-32`

`F-32=(9)/(5)C`

Multiply by 5/9 both sides

`(5)/(9)(F-32)=(5)/(9)((9)/(5)C)`

`(5)/(9)(F-32)=C`

Rewrite

`C=(5)/(9)(F-32)`