Question

What is the velocity of a beam of electrons that go undeflected when passing through crossed electric and magnetic fields of magnitude 1.4x10^4 V/m and 2.93x10^-3 T, respectively?

Answer 1

`v = 4.78 * {10}^(6) m {s}^( - 1)`

Step-by-step explanation:

Since the electrons are undeflected,

Magnetic force = Electric force

evB = eE

v = E/B

`v = \frac{1.4 * {10}^(4) }{2.93 * {10}^( - 3) } \\ = 4.78 * {10}^(6) m {s}^( - 1)`