Question

A reaction mechanism has the following elementary step as the slow step: B2A What is the rate law for this elementary step? O rate = k[B] O rate = k[A] [B]2 O rate = k[A] O rate = k [A] [B] O rate = k[A]2

Answer 1

r = k [ B ]

Step-by-step explanation:

• B → 2A

⇒ r = k [ A ]/2 = k [ B ]