Question

Given the following balanced redox reaction: 2 KMnO,+16 HCI2KCI+2 MnCl, +8 H20+5 Cl What is the stoichiometric factor relating KM O, and MnCl, representing the actual numbers of moles of each species that react and are produced according to the equation above?

Answer 1

The stoichiometric factor relating KMnO4 and MnCl2 is 1:1.

Step-by-step explanation:

The stoichiometric factor relating KMnO4 and MnCl2 can be determined from the balanced chemical equation given.

According to the equation, 2 moles of KMnO4 react and produce 2 moles of MnCl2. This means that the stoichiometric factor relating KMnO4 and MnCl2 is 1:1, where 1 mole of KMnO4 reacts with and produces 1 mole of MnCl2.