Question

a)A 10-mm-diameter Brinell hardness indenter produced an indentation 1.62 mm in diameter in a steel alloy when a load of 500 kg was used. Compute the HB of this material. (b) What will be the diameter of an indentation to yield a hardness of

Answer 1

Brinell hardness value = 241.26

Explanation:

As we know,

The mechanical properties of materials are very important when one wishes to design structures. One commonly measured mechanical property is the hardness. Various tests have been proposed and some are standardised according to the so-called ASTM requirements.

The Brinell hardness test suggests a Brinell hardness value (BH) according to the expression:

`BH=\frac{2P}{\pi D(D-\sqrt{D^(2)-d^(2))}}`

As per the given data:

P = 500 kg

D = 10 mm

d = 1.62 mm

On putting these values in BH

`BH=\frac{2* 500}{\pi * 10(10-\sqrt{10^(2)-1.62^(2))}}`

BH = 241.26

Hence, the Brinell hardness value = 241.26