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Help with 1, 2 and problem 3..

Help with 1, 2 and problem 3..-example-1
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User Rito
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1 Answer

7 votes
Okay!

Problem 1.)
7(3w-5)
The distributive property is just taking whatever number is on the outside and distributing it to what is in the parentheses.
So. We would do
7(3w)
We would get
21w
Then we do
7(-5)
-35
Now we can make our ending equation of
21w-35

2.)
(2-5q)(-3)
Again we do
(2)(-3)
-6
Then we would do
(-5q)(-3)
15q
Our equation would now be
-6+15q

3.)
2(3x-y)+ 5(x+2y)
First, we want to distribute these values. so
2(3x)
6x
Then
2(-y)
-2y
Then ending equation is 6x-2y

For 5(x+2y)
(5)(x)
5x
Then
5(2y)
10y
The ending equation is 5x+10y
Now we add our equations
6x-2y+5x+10y
11x+8y

answered
User Puckhead
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