Question

How many joules of heat energy are absorbed when 50.0 grams of water are heated from 50.0°C to 60.0°C?

Answer 1

`2090 \ j` needed to heat the amount of water giving.

Step-by-step explanation:

To solve this question we first need to know the specific heat of water which is given by 4.18 joules Per gram for increasing 1° of temperature. Now since one gram of water name one joules per gram so 2 grams will need twice of 4.18 that is 8.36 similarly 50 grams will need
`50 * 4.18 = 209`

Now we need to calculate the heat for 10° of change because temperature rises from 50° centigrade to 60° centigrade and difference in degrees

so heat needed is=
`209 * 10 = 2090 \ j`