Question

During a biopsy of the prostate, a thin needle is used to remove a series of cylindrical tissue samples. If the cylinders have a total length of 28.0 mm and a diameter of 0.100 mm, what is the total mass ???? (in grams) of tissue taken?

Answer 1

9.209×10^{-5} gm.

Step-by-step explanation:

Given: Length of the cylinder l= 28.0 mm

diameter of the cylinder d= 0.100 mm = radius r = 0.05 mm

The volume of the cylinder is given by V=
`\pi* r^2* l`

also, the density of the prostate generally is 419.3 kg/m^3

which is equal to = 0.4193 g/cm^3

mass= volume×density

mass= 0.4193×pi×r^2×l

mass=
`0.4193*\pi*2.8*0.005^2`

= 9.209×10^{-5} gm.

the total mass of the tissue in grams = 9.209×10^{-5} gm.