Question

A survey plat depicted to the right shows two lots that form a trapezoid. The measures of the parallel sides are 50.29 ft and 91.61 ft. The height of the trapezoid is 51.83 ft. Find the combined area of the two lots.

Answer 1

3677.3385ft²

Explanation:

The area of a trapezium=1/2(b+l)×Height

where;

b and l are parallel sides

b=the length of one parallel side, the shorter one=50.29 ft

l=the length of the other parallel side, the longer one=91.62 ft

h=is the perpendicular height to b

Replacing;

Area=1/2(50.29+91.61)×51.83=3677.3385ft²

Answer 2

The combined area of the two lots is
`3,677.34\ ft^2`

Explanation:

we know that

The area of a trapezoid is equal to

`A=(1)/(2)(b_1+b_2)h`

where

b_1 and b_2 are the parallel sides

h is the height of trapezoid

In this problem we have

`b_1=50.29\ ft\\b_2=91.61\ ft\\h=51.83\ ft`

substitute in the formula

`A=(1)/(2)(50.29+91.61)51.83`

`A=(1)/(2)(141.9)51.83`

`A=3,677.34\ ft^2`