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Prove (A-B)u(A-C)=A-(BnC)​

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Answer:

A-(B ⋂ ⋂C)=(A-B) ⋃ ⋃(A-C) If A-B={xlx ∈ ∈A and x ∉ ∉B} A-C={xlx ∈ ∈A and x ∉ ∉C} then (A-B) ⋃ ⋃(A-C)={xlx ∈ ∈A, x ∉ ∉(B and C) Let X=A and Y=(B ⋂ ⋂C) X-Y={xlx ∈ ∈X and x ∉ ∉Y} x ∉ ∉Y x ∉ ∉(B ⋂ ⋂C) x ∉ ∉(B and C) Therefore, A-(B ⋂ ⋂C)=(A-B) ⋃ ⋃(A-C).

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