Question

HOW LONG WILL AN "H" CYLINDER LAST IF IT HAS 1350 PSIG IN IT AND IT RUNS AT 6 LPM?

Answer 1

11.78 hours.

Explanation:

We are asked to find the time that an "H" cylinder will last having 1350 PSI of gas in it at a flow of 6 LPM.

`\text{Duration of tank (in minutes)}=\frac{\text{Tank pressure (in PSI)}*\text{Conversion factor}}{\text{Flow (LPM)}}`

`\text{Duration of H tank (in minutes)}=(1350* 3.14)/(6)`

`\text{Duration of H tank (in minutes)}=(4239)/(6)`

`\text{Duration of H tank (in minutes)}=706.5`

To convert the time in hours, we will divide 706.5 by 60 as i hour equals 60 minutes.

`\text{Duration of H tank (in hours)}=(706.5)/(60)`

`\text{Duration of H tank (in hours)}=11.775`

Therefore, it will take 11.78 hours to last the given cylinder.