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Assume n and m are integers. Prove if m divides n, then m divides -n

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Answer: So, if m divides n then n/m = x, and x is integer.

then -n/m = (-1*n)/m = -1*n/m = -1*x = -x.

So if x is integer, -x also is integer, then -n/m is integer and then m divides -n.

Where you used that in the integers set each number a has a opposite (also in the set ) such that a + b= 0, and b = -a = -1*a.

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User Nikola Yankov
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