Question

A 9.0 μF capacitor, a 13 μF capacitor, and a 16 μFcapacitor are connected in series. What is their equivalent capacitance? Express your answer using two significant figures.

Answer 1

Equivalent capacitance,
`C'=3.9\ \mu F`

Step-by-step explanation:

Capacitance,
`C_1=9\ \mu F`

Capacitance,
`C_2=13\ \mu F`

Capacitance,
`C_3=16\ \mu F`

Let C' is the equivalent capacitance of the combination of capacitors. It is given by :

`(1)/(C')=(1)/(C_1)+(1)/(C_2)+(1)/(C_3)`

`(1)/(C')=(1)/(9)+(1)/(13)+(1)/(16)`

`C'=3.99\ \mu F`

or

`C'=3.9\ \mu F`

So, their equivalent capacitance is
`3.9\ \mu F`. Hence, this is the required solution.