Question

If y = 0.02 sin (20x – 400t) (SI units), the wave number is

Answer 1

Wave number,
`k=20\ m^(-1)`

Step-by-step explanation:

The given equation of wave is :

`y=0.02\ sin(20x-400t)`............(1)

The general equation of the wave is given by :

`y=A\ sin(kx-\omega t)`..............(2)

k is the wave number of the wave

`\omega` is the angular frequency

On comparing equation (1) and (2) :

`k=20\ m^(-1)`

`\omega=400\ rad`

So, the wave number of the wave is
`20\ m^(-1)`. Hence, this is the required solution.