1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.13m 2.03 m 3.61 m 36.1 m Navigator F10 Delete Bac…

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asked Oct 25, 2020 183k views

1 Answer

Mike Seghers · Answer 1 · 2020-10-31T12:10:37+0000

Answer:

Molality = 1.13 m

Step-by-step explanation:

Molality is defined as the moles of the solute present in 1 kilogram of the solvent.

Given that:

Mass of
CH_3OH = 26.5 g

Molar mass of
CH_3OH = 32.04 g/mol

The formula for the calculation of moles is shown below:

$moles = (Mass\ taken)/(Molar\ mass)$

Thus,

$Moles= (26.5\ g)/(32.04\ g/mol)$

$Moles\ of\ CH_3OH= 0.8271\ moles$

Mass of water = 735 g = 0.735 kg ( 1 g = 0.001 kg )

So, molality is:

$m=\frac {0.8271\ moles}{0.735\ kg}$

Molality = 1.13 m