Question

A car is traveling 20 m/s and slows down at a uniform rate. It stops in 6 seconds. How far has it traveled in this interval?

Answer 1

Car travel a distance of 60.06 m in 6 sec

Step-by-step explanation:

We have given initial velocity v = 20 m/sec

Time = 6 sec

As the car stops finally so final velocity v = 0

From the first equation of motion

v = u+at (as the car velocity is slows down means it is a case of deceleration)

So v = u-at

`0=20-a* 6`

`a=3.33m/sec^2`

Now from second equation of motion
`s=ut-(1)/(2)at^2=20* 6-(1)/(2)* 3.33* 6^2=60.06m`