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Calculate that electric field that will apply a force of 25,000 N to an electron.

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Answer:


E=1.56* 10^(23)\ N/C

Step-by-step explanation:

Given that,

Electric force applied to the electron,
F=25000\ N

Charge on electron,
q=1.6* 10^(-19)\ C

We need to find the electric force acting on the electron. The electric field is given by :


E=(F)/(q)


E=(25000)/(1.6* 10^(-19))


E=1.56* 10^(23)\ N/C

So, the electric field acting on the electron is
1.56* 10^(23)\ N/C. Hence, this is the required solution

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