Question

If the original length of a specimen is L0 = 10"" and new length of the specimen after applied load is L = 12.5"". The value of true strain is: a) 0.5 b) 0.25 c) 0.223 d) 0.4

Answer 1

The correct answer is option 'b':0.25

Step-by-step explanation:

By definition of strain we have

`\epsilon =(L_f-L_o)/(L_o)`

where

`\epsilon` is the strain

`L_o` is the original length of specimen

`L_f` is the elongated length of specimen

Applying the given values we get

`\epsilon =(12.5''-10'')/(10'')=0.25`