Question

Find the specific volume and internal energy of compressed liquid water at 100 C and 10 MPa, using both the compressed liquid tables and the saturated liquid approximation. What percent error do you get using the saturated liquid approximation?

Answer 1

specific volume v = 0.0010385 m³/kg

and internal energy u = 416.23 KJ/kg

specific volume vf = 0.001043 m³/kg

and internal energy uf = 419.06 KJ/kg

% error in specific volume = 0.43 %

% error in internal energy = 0.679 %

Step-by-step explanation:

given data

pressure = 10MPa

temperature = 100 C

to find out

specific volume and internal energy and What percent error do you get

solution

we know pressure 10 MPa and temperature 100 C

so from compressed liquid water table we get

specific volume v = 0.0010385 m³/kg

and internal energy u = 416.23 KJ/kg

and

by using saturated liquid approx

from saturated water table of 100 C

specific volume vf = 0.001043 m³/kg

and internal energy uf = 419.06 KJ/kg

so

% error in specific volume is

% error in specific volume =
`(0.001043-0.0010385)/(0.0010385)` × 100

% error in specific volume = 0.43 %

and

% error in internal energy is

% error in internal energy =
`(419.06-416.23)/(416.23)` × 100

% error in internal energy = 0.679 %