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A small pad subjected to a shearing force is deformed at the top of the pad 0.12 in. The heigfit of the pad is 1.15 in. What is the shearing strain (rad) on the pad?

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Answer:

Shearing strain will be 0.1039 radian

Step-by-step explanation:

We have given change in length
\Delta L=0.12inch

Length of the pad L = 1.15 inch

We have to find the shearing strain

Shearing strain is given by


\alpha =tan^(-1)(\Delta L)/(L)=tan^(-1)(0.12)/(1.15)=5.9571^(\circ)

Shearing strain is always in radian so we have to change angle in radian

So
5.9571* (\pi )/(180)=0.1039radian

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User Huertanix
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