Question

What is the magnitude of the electric force between two point charges with Q1 = -1.5 C and Q2 = 0.8 C at a distance of 1 km?

Answer 1

F = -10800 N

Step-by-step explanation:

Given that,

Charge 1,
`q_1=-1.5\ C`

Charge 2,
`q_2=0.8\ C`

Distance between the charges,
`d=1\ km=10^3\ m`

We need to find the electric force acting between two point charges. Mathematically, it is given by :

`F=k(q_1q_2)/(d^2)`

`F=-9* 10^9* (1.5* 0.8)/((10^3)^2)`

F = -10800 N

So, the magnitude of electric force between two point charges is 10800 N. Hence, this is the required solution.