Question

3. A certain paint has a density of 0.914 g/mL. You need to cover a wall that is 7.6

meters long and 2.74 meters wide with a layer of paint that is 0.13 mm thick. What
volume of paint (in liters and gallons) is required? What is the mass (in grams and
pounds) of the paint layer?

How do i set this up?​

Answer 1

1) a) the volume in liters = 2.7 liter

b)the volume in gallons = 0.7132645414 gallons

2) a) the mass= 2467.8 g

b) mass in pounds = 5.4 pounds

Step-by-step explanation:

1) first we need to get the volume in m^3 by using the following format:

volume = the area of the wall * the thickness of the wall

when the area = the long * the wide

so by substitution:

volume = ( 7.6 m *2.74 m ) * 0.00013 m

= 0.0027 m^3

a) when 1 m^3 = 1000 liters

so the volume in liters = 0.0027 * 1000 = 2.7 liter

b) when 1 m^3 = 264.172 gallons

so the volume in gallons = 0.7132645414 gallons

2) the mass formula is:

mass = the volume * density

= 2700 ml * 0.914 g/mL

= 2467.8 g = 2.467 Kg

1 g = 0.00220462 pounds

so mass in pounds = 5.4 pounds