A petrol engine produces 20 hp using 35 kW of heat transfer from burning fuel. What is its thermal efficiency, and how much power is rejected to the ambient surroundings?

Question

asked Jun 13, 2020 133k views

1 Answer

Juhoautio · Answer 1 · 2020-06-18T16:13:52+0000

Answer:

efficiency =42.62%

AMOUNT OF POWER REJECTED IS 20.080 kW

Step-by-step explanation:

given data:

power 20 hp

heat energy = 35kW

power production = 20 hp = 20* 746 W = 14920 Watt [1 hp =746 watt]

$efficiency = (power)/(heat\ required)$

efficiency = (14920)/(35*10^3)

= 0.4262*10^100

=42.62%

b)
$heat\ rejected = heat\ required - amount\ of\ power\ generated$

= 35*10^3 - 14920

= 20.080 kW

AMOUNT OF POWER REJECTED IS 20.080 kW