Question

A 0.010 kg ball is shot from theplunger of a pinball machine.

Because of a centripetal force of0.025 N, the ball follows a
circulararc whose radius is 0.29 m. What isthe speed of the
ball?

Answer 1

v = 0.85 m/s

Step-by-step explanation:

Given that,

Mass of the ball, m = 0.01 kg

Centripetal force on the ball, F = 0.025 N

Radius of the circular path, r = 0.29 m

Let v is the speed of the ball. The centripetal force of the ball is given by :

`F=(mv^2)/(r)`

`v=\sqrt{(Fr)/(m)}`

`v=\sqrt{(0.025* 0.29)/(0.01)}`

v = 0.85 m/s

So, the speed of the ball is 0.85 m/s. Hence, this is the required solution.