Question

25 gallons of an incompressible liquid exert a force of 70 lbf at the earth’s surface. What force in lbf would 6 gallons of this liquid exert on the surface of the moon? The gravitational acceleration on the surface of the moon is 5.51 ft/s2.

Answer 1

froce by 6 gallon liquid on moon surface is 2.86 lbf

Step-by-step explanation:

given data:

at earth surface

volume of an incompressible liquid = Ve = 25 gallons

force by liquid = 70 lbf

on moon

volume of liquid = Vm = 6 gallons

gravitational acceleration on moon is am = 5.51 ft/s2

Due to incompressibility , the density remain constant.

mass of liquid on surface of earth
`= ( force)/( acceleration)`

`mass = (70lbf)/(32.2 ft/s2)`

mass = 2.173 pound

`density \rho = (mass)/(volume)`

`= (2.173)/(25) = 0.0869 pound/ gallon`

froce by 6 gallon liquid on moon surface is

Fm = mass * acceleration

= density* volume * am

= 0.0869 *6* 5.51

= 2.86 lbf